(x-3)^2=2x^2-14x+16

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Solution for (x-3)^2=2x^2-14x+16 equation: 



(x-3)^2=2x^2-14x+16

We move all terms to the left:

(x-3)^2-(2x^2-14x+16)=0

We get rid of parentheses

-2x^2+(x-3)^2+14x-16=0

We add all the numbers together, and all the variables

-2x^2+14x+(x-3)^2-16=0

We move all terms containing x to the left, all other terms to the right

-2x^2+14x+(x-3)^2=16

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